SUBNETTING CALCULATION OF OUM CAMPUS NETWORK
Figure 1: Simulation of network model
OUM has a total of 3 faculties and an IT Center:
- FSKKP: Fakulti Sistem Komputer & Kejuruteraan Perisian
- FSM: Fakulti Sains & Matematik
- FPI: Fakulti Pengurusan Industri
- IT Center with an Online Learning Server
SUBNETTING CALCULATION
- Method of Subnetting: FLSM (Fixed-Length Subnet Mask)
- The class we chose is Class C for this network. Class C IP addresses are used commonly for private networks. First three octets of a Class C network IP address is used to identify the network part and the remaining one octet is used to identify a host uniquely within that network.Class C networks are assigned to organizations with small to medium networks. The class C network is the most common network in use today. Class C networks have characteristics as below :
· range from 192.0.0.0 to 223.255.255.255.
· use the first 24 bits to determine the netid.
· three leftmost bits in a class C network are always 110 (192).
· next 21 bits are used to define network.
· there are 2, or 2,097,152, possible class C networks.
· 8 bits are used to define the hostid. Because an address with all bits set to 1 or all bits set to 0 is not allowed, the maximum number of hostids on a class C network is 2 minus 2, or 254 hostids
- The network address used in this project is 192.168.0.0.
Network Requirement
LAN | Computer and Servers | Router (LAN Gateway) | Switches | Total |
IT Center | 10 + 1 | 1 | 2 | 14 |
FSKKP | 45 | 1 | 4 | 50 |
FSM | 30 | 1 | 3 | 34 |
FPI | 20 | 1 | 2 | 23 |
- All subnets have the same number of addresses. The subnet with the largest host is FSKKP. We base the number of addresses for all networks on the addressing requirements for the largest network and the largest network is FSKKP requiring 50 addresses.
- We can use the formula of 2^bl-2 to find the number of hosts per subnet.
2^6 - 2 = 62 hosts
From this we know that each subnet will have 62 hosts.This meets the current requirement for at least 50 addresses, with a small allowance for growth. This also leaves 26 network bits (32 total bits - 6 host bits).
- Because there are four networks in our internetwork, we will need four blocks of 64 addresses each, for a total of 256 addresses. We will use the address block 192.168.0.0/26. This provides address range from 192.168.0.0 to 192.168.0.255.
Detailed Explanation
-192.168.0.0 = 11000000.10101000.00000000 .00000000
-Netmask: 255.255.255.192 = 11111111.11111111.11111111.11000000
-The first 24 bits are reserved for net id and next 2 bit are for subnet and last 6 bit for host.
Zero subnet
192.168.0000 0000.0000 0000 = 192.168.0.0 (NA)
192.168.0000 0000.0011 1111 = 192.168.0.63 (BA)
1st subnet
192.168.0000 0000.0100 0000 = 192.168.0.64 (NA)
192.168.0000 0000.0111 1111 = 192.168.0.127 (BA)
2nd subnet
192.168.0000 0000.1000 0000 = 192.168.0.128 (NA)
192.168.0000 0000.1011 1111 = 192.168.0.191 (BA)
3rd subnet
192.168.0000 0000.1100 0000 = 192.168.0.192 (NA)
192.168.0000 0000.1111 1111 = 192.168.0.255 (BA)
SUBNET | |
ZERO SUBNET | Network Address = 192.168.0.0 |
IP Range = 192.168.0.1 to 192.168.0.62 | |
Broadcast Address = 192.168.0.63 | |
1ST SUBNET | Network Address = 192.168.0.64 |
IP Range = 192.168.0.65 to 192.168.0.126 | |
Broadcast Address = 192.168.0.127 | |
2ND SUBNET | Network Address = 192.168.0.128 |
IP Range = 192.168.0.129 to 192.128.0.190 | |
Broadcast Address = 192.168.191 | |
3RD SUBNET | Network Address = 192.168.0.192 |
IP Range = 192.168.0.193 to 192.168.0.254 | |
Broadcast Address = 192.168.0.255 | |
BROADCAST SUBNET | Network Address = 192.168.1.0 |
IP Range = 192.168.1.1 to 192.168.1.62 | |
Broadcast Address = 192.168.1.63 |
FSKKP (ZERO SUBNET) | The FSKKP network required 50 addresses. |
The address block is 192.168.0.1 to 192.168.0.62 | |
Unused – 12 addresses. | |
FSM (1ST SUBNET) | The FSM network required 34 addresses. |
The address block is 192.168.0.65 to 192.168.0.126 | |
Unused – 28 addresses. | |
FPI | The FPI network required 23 addresses. |
The address block is 192.168.0.129 to 192.168.0.190 | |
Unused – 39 addresses. | |
IT CENTER | The IT center network required 14 addresses. |
The address block is 192.168.0.193 to 192.168.0.254 | |
Unused – 48 addresses. | |
WAN | The wan network required 2 addresses only. |
The address block is 192.168.1.1 to 192.168.1.62 | |
Unused – 60 addresses. | |
As for the assignment of IT Center as another subnet with their own network address we take the network 192.168.0.192 and from this network address,
Network Address: 192.168.0.192 IP Range: 192.168.0.193 to 192.168.0.254 B. Address: 192.168.0.255 |
Hence we have assigned the 4th available address as the address of the OnlineLearning System Server which is 192.168.0.196.